Genetic Solutions For PSLO Coursework Example

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Let XB = Normal vision allele
Let Xb = Red-green color blindness allele
Data collection/Selection
Parent genotypes: XBY * XBXb
Parent 1 gametes: XB , Y
Parent 2 Gametes: XB , XbAnalysis
Parental Gametes XB Y
XB XBXB XBY
XbXBXbXbYF1 genotypic ratio= 1 XBXB : 1 XBXb : 1 XBY : 1 XbYF1 phenotypic ratio= 1Normal vision girl: 1 red-green blindness carrier girl: 1 Normal vision boy: 1 red-green color blind boy
Conclusion
From the phenotypic ratio, we can conclude that there is 50% chance of the children born to these parents having red-green color blindness. Therefore, there is a half chance of a boy child having the red-green color blindness and half chance for the girl being a carrier for the red-green color blindness trait.
Subject Matter
The couple will father a female child who is not red-green color blind. Since normally the girl takes the X-chromosome from the father and in this case the father has normal vision. Therefore, the mother being a carrier will pass red-green color blindness from the mother.
2) Let R = Purple flower color and r = white flower colorLet D = Dark Green leaves and d = light green leaves
Data collection
Parent Genotypes: RRDd * RrDdParent 1 Gametes: RD, Rd
Parent 2 Gametes: RD, Rd, rD, rd
Parental Gametes RD Rd
RD RDRD RdRD
Rd RDRd RdRd
rD RDrD RdrD
rd RDrd Rdrd
F1 genotypic ratio= 1RDRD: 2RdRD: 1RdRd: 1RDrD: 1RdrD: 1RDrd:1Rdrd
F1 phenotypic ratio= 6Purple flower dark green leaves: 2purple flower and light green leaves
Conclusion
¼ of the offspring will have purple flower color with light green leaves.

Subject Matter
The parents above will not be able to produce offspring with white flower color. This is because the gene responsible for white flower color is recessive all through.