ANOVA Table Coursework Example

Given the aggression scores below for Outcome A of the sleep deprivation experiment, verify that, as suggested earlier, these mean differences shouldn’t be taken seriously by testing the null hypothesis at the .05 level of significance. Use the computation formulas for the various sums of squares and summarize results with an ANOVA table.
HOURS OF SLEEP DEPRIVATION
ZERO TWENTY-FOUR FORTY-EIGHT
342
584
766
564 Grand mean = 5

The F value was 0.75, while the p-value was 0.51. Since the p-value for the ANOVA was greater than 0.05 (p=0.51) it could be concluded that there was no significant depression in aggression scores across several levels of sleep deprivation. Hence, sleep deprivation should not be considered as a determinant of aggression scores with respect to study population that was included in the trial.
*16.10 Another psychologist conducts a sleep deprivation experiment. For rea-sons beyond his control, unequal numbers of subjects occupy the differ-ent groups. (Therefore, when calculating in SS between and SS within, you must adjust the denominator term, n, to reflect the unequal numbers of subjects in the group totals.) (a) Summarize the results with an ANOVA table. You need not do a step-by-step hypothesis test procedure. ΣT2n
HOURS OF SLEEPDEPRIVATION
ZEROTWENTY-FOUR FORTY-EIGHT
147
3712
6610
29
1

ANOVA Summary 
Source SS df MS F P
Treatment[between groups]
Error Ss/Bl (b) If appropriate, estimate the effect size with h2. (c) If appropriate, use Tukey’s HSD test (with –n 5 4 for the sample size, n) to identify pairs of means that contribute to the signifi cant F, given that –X0 5 2.

60, –X24 5 5.33, and –X48 5 9.50. (d) If appropriate, estimate effect sizes with Cohen’s d. (e) Indicate how all of the above results would be reported in the literature, given sample standard deviations of s 0 5 2.07, s 24 5 1.53, and s 48 5 2.08.
Turkey’s HSD test results indicate that there was a significant difference between aggression levels with respect to hours of sleep deprivation. However, there was no significant difference in the mean aggression levels between individuals who were exposed to 0 hours of sleep deprivation and 24 hours of sleep deprivation ( p>0.05). However, there was a significant difference in the mean aggression levels between individuals who were exposed to 0 hours of sleep deprivation and 48 hours of sleep deprivation ( p<0.01). On the other hand, there was no significant difference in the mean aggression levels between individuals who were exposed to 48 hours of sleep deprivation and 24 hours of sleep deprivation ( p>0.05).
HSD[.05]=3.98; HSD[.01]=5.46
M1 vs M2 nonsignificant
M1 vs M3 P<.01
M2 vs M3 nonsignificant
*16.12 For some experiment, imagine four possible outcomes, as described in the following ANOVA table.A. SOURCE SSdfMS F
Between 900 33003Within 8000 80 100
Total 8900 83
B. SOURCE SSdfMS F
Between 1500 3 500 5
Within 8000 80 100
Total 9500 83